Hi as the title states I have an issue understanding what this calls for?
#if One Function && another Function
Does this mean if I call both functions it will begin the if statement?
There is no sample code, just a question of formating I suppose.
Thanks!
Maybe you should post the smallest and simplest program that illustrates the crux of your question.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
OK.
F_funtionA, F_FunctionB are the functions lets say.
#if (F_funtionA && F_functionB)
unsigned char main(unsigned char variable);
#define F_FunctionC
#endif
and if I want to use the functionC do i need to call first A, b? or is there something I am not understanding about &&.
Thanks
Do you mean:
The && is a Boolean operator. Google it. Assuming function_1 and function_2 return a Boolean of some kind (TRUE/FALSE, 0 / non-zero), then the && operator will perform an AND operation on their results. So, for instance, if you have the following:Code:if( function_1() && function_2() ) do_something();
In this case, the door will only open is the user has access (user_has_access returns TRUE) *AND* the door is working (door_is_working returns TRUE). Otherwise it won't do anything.Code:if(user_has_access() && door_is_working()) open_door();
There is a slight trick as well here that catches beginner's - C uses short-circuit evaluation. If the user_has_access call returns FALSE, then there's no point checking if the door_is_working. It won't make any difference to the outcome. So the program will NOT call door_is_working at all in that instance. Some people don't realise that and their program can go wrong because they expect it to be checked anyway.
- Compiler warnings are like "Bridge Out Ahead" warnings. DON'T just ignore them.
- A compiler error is something SO stupid that the compiler genuinely can't carry on with its job. A compiler warning is the compiler saying "Well, that's bloody stupid but if you WANT to ignore me..." and carrying on.
- The best debugging tool in the world is a bunch of printf()'s for everything important around the bits you think might be wrong.
Hey thank you very much! So i should call something like:
user_has_access=1;
door_is_working=1;
Then my open_door(5seconds or something) function should work? If 1 is predefines as true?
both #if and #endif indicate that he is talking about preprocessor directives. In that case those things are not function as such, at least not runtime functions. You would need to post what F_funtionA and F_functionB really are in order for us to be able to tell how you could get the desired outcome.
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Advice: Take only as directed - If symptoms persist, please see your debugger
Linus Torvalds: "But it clearly is the only right way. The fact that everybody else does it some other way only means that they are wrong"
They are made up functions in a sample file like the sample code i posted above. I believe I figured it out, now just to set them = to "True" will depend on whether 1 or 0 is true.
What is a function? Define a function in code as an example.
Frankly, I think that you are either misunderstanding something pretty basic, or simply are using the wrong terminology. That is why I asked for you to elaborate with a program earlier, but you only posted a code snippet that did not have much context.
Look up a C++ Reference and learn How To Ask Questions The Smart Way
Ok I have a statement like this in a header file
#if (F_A && F_B)
unsigned char secondary (unsigned char type);
#define F_C
#define F_D
#endif
I am trying to call for F_C and it says its undefined. I think it's because i have to first say F_A, F_B are true. I cannot put actual code due to the sensitivity of my project.
@tzzr101:
Do you know the difference between a MACRO, function, and function prototype?
Because your questions implies you have no idea that there is is any difference between the three things.
Tim S.
"...a computer is a stupid machine with the ability to do incredibly smart things, while computer programmers are smart people with the ability to do incredibly stupid things. They are,in short, a perfect match.." Bill Bryson
> I cannot put actual code due to the sensitivity of my project.
So make something simple, which seems to resemble the problem, using symbols like FOO and BAR
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
I find it very hard to believe that someone with C skills that are to the point of not knowing about the proprocessor could be involved in such a secretive project. If the code you're using is that important, then you would have sufficient mentoring of someone else at your company, partly to keep an eye on the new employee.
Also, the act of hiding API methods behind such proprocessor directives is very very common practice by Microsoft, so I highly suspect its one of those. E.g. you just need to define WIN32_WINNT as some version or higher.
Well I guess when you can't work it out and can't provide enough info here then I guess you'll consider other options.
My homepage
Advice: Take only as directed - If symptoms persist, please see your debugger
Linus Torvalds: "But it clearly is the only right way. The fact that everybody else does it some other way only means that they are wrong"
I did, its above. Thats literally the code and im trying to call the function F_C.
No i do not. I am very new to programming. I'll check it out thanks!
Thanks for the harrassment. I am an intern, forced to do programming and have no skills in doing so. I don't know why, but I'm not the boss I do what I'm told. They don't help me either it's frusterating believe me. anyway thanks for the windows tip.
