How to convert hexadecimal into floating point?
I'm trying to convert 4 hex register into floating point value using IEEE 754 floating point format.
My device will reply 4 register value.
The problem is that it always reply for example 0x10 as 10 when i use getc() hence using char variable to store it is not ideal.
Code:union { char c[4]; float f; } conv;
Any solution for this problem?
This is something I've had for a while that converts a float to four bytes.
It might help
Code:void float_to_bytes() { unsigned char *pbyte = (unsigned char *) &aFloat; for (findx=0; findx<sizeof(float); findx++) { bytes[findx] = *pbyte; pbyte++; } // findx sbuffer[floatindex] = bytes[0]; floatindex++; sbuffer[floatindex] = bytes[1]; floatindex++; sbuffer[floatindex] = bytes[2]; floatindex++; sbuffer[floatindex] = bytes[3]; floatindex++; }
I have the reverse as well,
Here ya go:
You can call it like this:Code:float Float(charunsigned *const p) { // convert four bytes to float float val; memcpy(&val,p,sizeof val); return val; }
Where bytes is the same 4 byte array as the first example.Code:Float(bytes);
Last edited by xArt; 03-10-2013 at 09:35 PM.
I'm still an amateur in C language, show me an example for your second code?
For example, my device will reply 4 different hex register 43, 70, 80, 00. The conversion output will be 240.5.
Last edited by zenniz; 03-11-2013 at 12:17 AM.
The order of the bytes depends on the platform you're using,
but:
Code:float number; char bytes[4]; bytes[0] = 0x43; bytes[1] = 0x70; bytes[2] = 0x80; bytes[3] = 0x00; number = Float(bytes);
