Hello Everyone,
My task is to convert an inputted number i.e. 234567 and print out the words of each digit so it would print "two three four five six seven".
I don't even know where to start. All I know is that i need or should be using switch statements.
Any help will be greatly appreciated. Thanks in advance!
If you read in the number as a string str, then the digit '2' is located at str[0].
You should run it in a loop and process each digit in your str.Code:switch(str[0]) { case '1': printf("one"); break; case '2': printf("two"); break; ... }
Okay. So I understand what you are talking about and get it, but how do I increment the string?
Thanks.
You should probably use a for loop. For example if your str is "12345" then you could do something likeOriginally Posted by McZiploc
Code:for (int i=0; i < 5; i++) { switch(str[i]) { ... } }
Okay, thank you again but I have a small problem. I'm trying to put a "-" between the words but having some trouble. Here's my code
Code:#include <stdio.h> #include <strings.h> int main() { char number[255]; int n, digits, x=0, num_length; printf("Enter a number: "); scanf("%s", &number); num_length = strlen(number); for(n=0; n<=num_length; n++){ switch(number[n]){ case '0': printf("zero"); break; case '1': printf("one"); break; case '2': printf("two"); break; case '3': printf("three"); break; case '4': printf("four"); break; case '5': printf("five"); break; case '6': printf("six"); break; case '7': printf("seven"); break; case '8': printf("eight"); break; case '9': printf("nine"); break; } for(x=0; x<=n; x++){ printf("-"); } } return 0; }
Your for loop should probably be:
for (n=0; n < num_length; n++)
Suppose your string is 10 characters. Then the ten characters are number[0], number[1], ..., number[9]
For printing dashes in between, you probably should add something inside your case labels.
Code:case '1': printf("one"); printf("-"); break;
Thank you sooo much. Thanks for your time. I finally understand this.
