Your problem is here:
Do not put the semicolon after the "while()" - if you do so, it constitutes the statement you want to perform, which does nothing. I.e. what you have written is actually:Code:while ( (c=getchar()) !=EOF);
Code:while ( (c=getchar()) !=EOF) /* do nothing */; /* c is now EOF */
Programming and other random guff: cat /dev/thoughts > blogspot.com (previously prognix.blogspot.com)
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"The largest-scale pattern in the history of Unix is this: when and where Unix has adhered most closely to open-source practices, it has prospered. Attempts to proprietarize it have invariably resulted in stagnation and decline."
Eric Raymond, The Art of Unix Programming
Partially true. Read my post, because there is another logical error tooOriginally Posted by JohnGraham
Code - functions and small libraries I use
It’s 2014 and I still use printf() for debugging.
"Programs must be written for people to read, and only incidentally for machines to execute. " —Harold Abelson
