Thread: pointers

Originally Posted by std10093

You pass the array as I said and you handle it normally (of course not as you say...)

No. Your example only considers single-dimensional arrays. With an n-dimensional array passed as input into a function, the compiler needs to "know" about the the size of the highest n-1 dimensions of the array. In addition, the programmer needs to know the size of the lowest dimension of the array as well as where the array begins in memory. So in total, you must design your function to accept n+1 parameters. This fact is true independent of whether you use the C99 syntax or C89 syntax. Using the C99 syntax simply lets you use indices inside the function in a natural mathematical way, i.e. "in the normal way".

Yes is the answer. When you want to pass a n dimensional array you pass n stars as pointers and n dimensions. So simple.

Also, I suppose you understood your mistake before... I guess actually it won't even compile. Tip : Compile the code before you post it

Enough said and this thread is solved.

Bye