thise is the code!
its give me an error on the running stage.
Code:#include "stdafx.h"#include <stdio.h> #include <conio.h> #include <string.h> #include <stdlib.h> int main() { char _str[100]; int i=0,count_str=0; printf("enter string up to 10 letters!"); gets (_str); count_str=strlen(_str); //for (i=0;i<10;i++){ // scanf("%s",&_str[i]); //} for(i=(count_str-1);i>=0;i--) printf("%s\n",_str[i]); getch(); return 0; }
everything seems to be ok but still ,not working.
iam lost.
In printf() format, you are using %s, but giving it the parameter of a char _str[i]. Also, you're printing the string backwards, is that what you want, kind of a "stepped" print out:
Is what I mean by "stepped". Is that what you want?Code:e ge rge orge eorge George
Lastly, variables with a leading underline, and double underline, are usually reserved for the compiler, and shouldn't be used by the programmer, at all.
Do you want to print the string out backwards? And how many times? The entire string each time, or "stepped" in length?
Last edited by Adak; 01-09-2013 at 07:26 AM.
i need to scanf string and yes print it backwards one time .
thank you very much for your quick answer
no sir,
it goes like thise ...
good
d
o
o
g
or
d o o g
> printf("%s\n",_str[i]);
Use %c to print individual characters.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Read the string with
Never use gets!!!Code:scanf("%s",...);
Then you have in the buffer the string.
In a loop start printing every character of it, starting from the end of it.
Where is the end of the string?
Use strlen to find out. Be careful of the null terminator of the strings.
In the loop, you will have your counter decreasing until it reaches the zero (including)
Code - functions and small libraries I use
It’s 2014 and I still use printf() for debugging.
"Programs must be written for people to read, and only incidentally for machines to execute. " —Harold Abelson
its working ....tankns a loot.Code:#include "stdafx.h"#include #include #include #include int main(){char _str[100];int i=0,count_str=0;printf("enter string up to 10 letters!");gets (_str);count_str=strlen(_str);//for (i=0;i=0;i--)printf("%c\n",_str[i]);getch();return 0;}
Code:#include "stdafx.h"#include <stdio.h> #include <conio.h> #include <string.h> #include <stdlib.h> int main() { char _str[100]; int i=0,count_str=0; printf("enter string up to 10 letters!"); gets (_str); count_str=strlen(_str); //for (i=0;i<count_str;i++){ // scanf("%c",&_str[i]); //} for(i=(count_str-1);i>=0;i--) printf("%c\n",_str[i]); getch(); return 0; }
great forum...thanks again (-:
Is post #7 not visible?????
Code - functions and small libraries I use
It’s 2014 and I still use printf() for debugging.
"Programs must be written for people to read, and only incidentally for machines to execute. " —Harold Abelson
soon i will start studying about pointers.
thanks you saved me.
I refreshed it once, and did not see several posts in this thread. After refreshing twice more, I see them all, and that it's solved.
You should listen to std10093 and stop using gets().
We'll keep reminding you each time you use gets(), so it's best to stop using it. It is a completely unsafe function with no place in modern programs.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
i will thanks for the advice
