Thread: What is wrong with this program

Originally Posted by Moody Barrawi

Ooh and I need to know the parameters of the two function like what kinds are they. So I made out that
Double_trouble = *p: Input and output
Y: Input
Trouble = *x: Input
*Y:?
So where am I going wrong here?

I think the problem is of naming. Each function has its own local name that is unrelated to the others. Let's introduce a simple renaming scheme:

1. main keeps the names x, y for its variables.
2. trouble appends the number "1" to each of its local variable names.
3. double_trouble appends the number "2" to each of its local variable names.

By doing this, the program is not changed at all, but it may become easier to track the different symbols

Code:

#include <stdio.h>

void double_trouble(int *, int);
void trouble(int *, int *);

int main(void)
{
    int x, y;
    trouble(&x, &y);
    printf("x=%d,y=%d\n",x, y);
    return(0);
}

void trouble(int *x1, int *y1)
{
    double_trouble(x1, 7);
    double_trouble(y1, *x1);
}

void double_trouble(int *p2, int y2)
{
    int x2 = 10;
    *p2 = 2 * x2 - y2;
}

Originally Posted by Moody Barrawi

And the program still wouldn't run. What the F is wrong?

It ran fine for me and gave an answer. And there is no `F' in that program, only x1, y1, etc.

If you're having trouble you have to say what didn't work exactly. Did the compiler give you an error message or what

The code seems good. What's the error you get?

Don't say the word that starts with F :O

Originally Posted by QuantumNut

I don't see anything wrong with the code...

That was an echo :P

//mine was just typed simultaneously with the one of the tutorial guy :P

Originally Posted by Crossfire

program ran for me, got x=13,y=7, althoug i have no clue what the point of it is!!! lol

I got the same results. It can be for training purposes, or just for fun