Thread: Print character x times based on user's input

Hi!

So first of all, please keep in mind that I have just began with C, I took CS50x from Harvard and so far I have a very limited knowledge, so my question may seem very simple.

What I have to do is to create a "pyramid" which has to look something like this:

Code:

   #
  ##
 ###
####

The user has to firstly input an integer to declare how many rows the pyramid is going to have.

What I have so far

Code:

#include <stdio.h>
#include <cs50.h>
#include <math.h>


int main(void)
{
    //create an infinite loop that will check the value 
    while (1)
    {
            //get an integer from the user which will define the height of the pyramid
            printf("Enter the height of the pyramid! The value has to be in range 3 to 24.\n");
            int h = GetInt();
        
            //if a value is in the range, then proceed to create a pyramid
            if (h<=24 && h >= 3)
            {
                for(int i = h; i > 0; i--)
                {
                     printf("row\n");               
                }
                
                
                break;   
            }
            
            //otherwise continue loop and ask for an another value
            else
            {
                printf("You have entered the invalid value, please try again.\n");
            }
    }
    return 0;


}

What I am struggling with currently is to figure out how to print out space (h - 1) times

I would really appreciate any help, but rather then just giving me a finished code I would appreciate a "guidance". Thank you

Well I guess I wrote it wrongly. What I am struggling with is to create a loop that will print out space h-1, h-2, h-3 .... h - h times

Originally Posted by Kecupochren

I would really appreciate any help, but rather then just giving me a finished code I would appreciate a "guidance". Thank you

Hello there,

What I understand from your problem (well, actually you may need to modify a bit my solution for the value range part inside a loop) is that:

Assuming that numberOfRows is the number of rows:

- For each row N you have to insert numberOfRows - N spaces before start printing sharps

- For each row N you have to print N times the sharp character

- And finally insert a new line character


You can try the following:

Code:

#include <stdio.h>

int main(int argc, char *argv[])
{
    int numberOfRows = 0;
    int rowNumber = 0;
    int counter = 0;
    
    // start by asking the user the number of rows
    printf("Enter the number of rows: ");
    scanf("%d",&numberOfRows);
    
    for (rowNumber = 0 ; rowNumber <= numberOfRows ; rowNumber++)
    {
        // For each row N you have to insert numberOfRows - N spaces
        // before start printing sharps
        for (counter = 0 ; counter < numberOfRows - rowNumber ; counter++)
            printf(" ");
            
        // For each row N you have to print N times the sharp character
        for (counter = 0 ; counter < rowNumber ; counter++)
            printf("#");
        
        // And finally a new line character for the next loop iteration
        printf("\n");
    }
    
    
    return 0;
}

Which gives the following result (I tested on Linux)

Code:

$ gcc -Wall testscript.c -o testscript
$ ./testscript
Enter the number of rows: 0

$ ./testscript
Enter the number of rows: 1
 
#
$ ./testscript
Enter the number of rows: 2
  
 #
##
$ ./testscript
Enter the number of rows: 3
   
  #
 ##
###
$ ./testscript
Enter the number of rows: 4
    
   #
  ##
 ###
####
$ ./testscript
Enter the number of rows: 5
     
    #
   ##
  ###
 ####
#####
$

Regards,
Dariyoosh

Can be done in one loop using variable field width formatting for both the spaces and the number of '#' shown from a predefined array containing 24 '#' (specified as maximum needed) characters.