Thread: joining codes

I need help with completing and some codes together
Key aims: 1. The user can select a departure station
2. The user can select an arrival station
3. the user can select either single or return journey.

i need the code to be able to show the result of the arrival and departure station and a way to count the stops so i could add to the calculation.

Code:

#include <stdio.h>

void station1()
{
    printf( "Ashford Station" );
}
void station2()
{
    printf( "Brentworth Station" );
}
void station3()
{
    printf( "Canonbury Cross Station" );
}
void station4()
{
    printf("Dowgate Station");
}
void station5()
{
    printf("Edbury Station");
}
void station6()
{
    printf("Fenchurch Street Station");
}
void station7()
{
    printf("Gresham Station");
}
void station8()
{
    printf("Hampstead Station");
}
void station9()
{
    printf("Islington Station");
}
void station10()
{
    printf("Jamaica Road Station");
}
int main()
{
    int input;

    printf( "1. Ashford Station\n" );
    printf( "2. Brentworth Station\n" );
    printf( "3. Canonbury Cross Station\n" );
    printf( "4. Dowgate Station\n");
    printf( "5. Edbury Station\n");
    printf( "6. Fenchurch Street Station\n");
    printf( "7. Gresham Station\n");
    printf( "8. Hampstead Station\n");
    printf( "9. Islington Station\n");
    printf( "10. Jamaica Road Station\n");
    printf( "11. Exit\n" );
    printf( "Arrival Station:" );
    scanf( "%d", &input );
    printf("Depature Station:");
    scanf("%d",&input);
    switch ( input ) {
        case 1:
            station1();
            break;
        case 2:
            station2();
            break;
        case 3:
            station3();
            break;
        case 4:
            station4();
            break;
        case 5:
            station5();
            break;
        case 6:
            station6();
            break;
        case 7:
            station7();
            break;
        case 8:
            station8();
            break;
        case 9:
            station9();
            break;
        case 10:
            station10();
            break;
        case 11:
            printf( "Thanks\n" );
            break;
        default:
            printf( "Invaild input, quitting!\n" );
            break;
    }
    getchar();

}

I have a price code which i can't complete

Code:

#include<stdio.h>
int main(void)
{float  ticketcost=2.00f, returncost=0.0f, stops =0.0f, singlecost=0.0f, priceofjourney =0.0f;

    {int choice;
    printf("\nEnter Either 1 for Single Journey or 2 for Return Journey:");
    scanf("%d", &choice);
    if (choice==1)
    {
        printf("\nSingle Journey:");
        scanf("%f", &singlecost);
        }
        else if (choice==2)
      {
            printf("\nReturn Journey:");
        scanf("%f", &returncost);
        }
        else
        {
            printf("\nInvalid Option");
        }
    {float  ticketcost=2.00f, returncost=0.0f, stops =0.0f, singlecost=0.0f, priceofjourney =0.0f;


  singlecost=ticketcost*stops;
  returncost=singlecost * (singlecost/2);
  printf("\nPrice of single journey = %.2f\n\n", singlecost);
  printf("\nprice of return journey = %.2f\n\n", returncost);

 getchar();

return 0;}
    }
}

I would really appreciate any advice or help.
thanks

In main you are assigning departure station and arrival station to the same variable:

Code:

printf( "Arrival Station:" );
scanf( "%d", &input );
printf("Depature Station:");
scanf("%d",&input);

so you are losing the 'arrival station' value. Once you keep the two values separate you can calculate the number of station by arrival - departure. If it's negative make it positive.

Please, please, please ... learn to use arrays!

Code:

#include <stdio.h>

int main(void) {
    int input, i;
    const char *station[] = {
        "Ashford Station",         "Brentworth Station",
        "Canonbury Cross Station", "Dowgate Station",
        "Edbury Station",          "Fenchurch Street Station",
        "Gresham Station",         "Hampstead Station",
        "Islington Station",       "Jamaica Road Station"
    };

    for (i = 0; i < 10; i++) {
        printf("%d. %s\n", i + 1, station[i]);
    }
    printf("11. Exit\n");
    /* code commented out
    ** because it has no effect other than
    ** cluttering the display
    printf("Arrival Station: ");
    scanf("%d", &input);
    */
    printf("Departure Station: ");
    scanf("%d", &input);
    if ((1 <= input) && (input <= 11)) {
        if (input == 11) printf("Thanks\n");
        else printf("%s\n", station[input - 1]);
    } else {
        printf("Invalid input, quitting!\n");
    }
    getchar();
    return 0;
}

If you use an array to store all those stations and 'for loops' to read from it, it'll make it so much easier to print/read from them

C++ Tutorial - 10 - Beginning Arrays - YouTube

once you figure it out it'll make your life much easier and your code a lot better

thanks for the help, i'm stuggling to caculate the diffrence between the arrival and departure, any ideas with for that?

Originally Posted by nonoob

In main you are assigning departure station and arrival station to the same variable:

Code:

printf( "Arrival Station:" );
scanf( "%d", &input );
printf("Depature Station:");
scanf("%d",&input);

so you are losing the 'arrival station' value. Once you keep the two values separate you can calculate the number of station by arrival - departure. If it's negative make it positive.

please how would i calculate that? thanks