Thread: Compare input with array element

heya,

sorry stupid question but:

how can I compare my input with a string element of an array?

EDIT: check post below for source code

Hm obviously the "code" of
strcmp(codes[i].country, code)
is the issue. I just don't know how I could "parse" code to a string to compare the arraystring with the input code :/

Thanks in advance!

Use a for loop:

Code:

int checkMatch() {
  int i = 0; 
  for ( i=0; i<sizeof codes/sizeof *codes; i++ ) {
    if ( strcmp( codes[i].country, code ) == 0 ) {
      // as before
      return i;
    }
  }
  return -1;
}

It's probably useful to return the index (i.e. i) in the checkMatch function in case your main function might want to do anything with it. -1 is a 'no match' value, as the -1th element doesn't exist.

I'm also not entirely sure what your if statements with inputcount is meant to do...

Ah well I fear the issue lies within my messy code rather than the strcmp method itself

Code:

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <String.h>
#include <stdbool.h>
#define ZEICHEN 1024

int inputcount = 0;
char code[ZEICHEN];
bool numeric = false;
bool alpha = false;

    typedef const char* const CountryNameType;
    typedef const unsigned int DialingCodeType;
    struct country_code
    {
        CountryNameType country;
        DialingCodeType code;
    }
    codes[] =
    {
        {"Austria" , 43},
        {"Belgium", 32},
        {"Cyprus", 357},
        {"Czech Republic", 420},
        {"Germany", 49},
        {"Denmark", 45},
        {"Estonia", 372},
        {"France", 33},
        {"Finland", 358},
    };

int len = sizeof(codes)/sizeof(int)/2;

void statusCheck()
{
    if (numeric && alpha)
    {
        printf("Unknown country name.\n");
        return;
    } else if (!numeric && alpha)
    {
        for (int i=0; i<len; i++)
        {
            if (strcmp(codes[i].country, code) == 0)
            {
                printf("Match: %d\n", codes[i].code);
                return;
            }
        }
    } else if (numeric && !alpha)
    {
        for (int i=0; i<len; i++)
        {
            if (codes[i].code == atoi(code))
            {
                printf("Match: %s\n", codes[i].country);
                return;
            }
        }
    }
}
void checkMethod()
{
    numeric = false;
    alpha = false;
    inputcount = 0;
    printf("Enter dialing code or country name: ");
    while (1)
    {
        scanf("%c", &code[inputcount]);
        if (code[inputcount] != '\n')
        {
            inputcount++;
            if (isalpha(code[inputcount-1]))
            {
                alpha = true;
            }
            else if (isdigit(code[inputcount-1]))
            {
                numeric = true;
            }
        }
        else
        {
            statusCheck();
            checkMethod();
        }
    }
}

int main()
{
    checkMethod();
    return 0;
}

You are going out of bounds in the for in line 43. I guess you are computing variable len incorrectly.

In line 55 a DialingCodeType (int) is being compared to a CountryNameType (char*). You'll need to look into atoi or similar functions to compare the two.

It's going to be easier to do an scanf( "%s", code );, then check [FONT=Courier New]code[0][/FONT for alphanumericy rather than read in character by character.

EDIT: nm that wasn't the issue...

thx for the help updated the source code

the numeric input is working as it should now with atoi

the string input still won't work though =/

Maybe it really is because of the \n linebreak of the input?

Maybe you should test that all of the variables are of the same type, i.e something like.

Code:

int main( void ) {
  char *code;
  int j = 0; 
  char *codes[3] = { "abc", "123", "a12" }; 

  for ( j=0; j<3; j++ ) {
    int numDigit, numAlpha, len, i;
    code = codes[j];

    printf( "Testing %s: ", code ); 

    numDigit = 0;
    numAlpha = 0; 
    len = strlen( code ); 

    for ( i=0; i<len; i++ ) {
      if ( isdigit( code[i] ) ) numDigit ++; 
      if ( isalpha( code[i] ) ) numAlpha ++; 
    }

    if ( numDigit == len ) {
      printf( "All digit\n" ); 

    } else if ( numAlpha == len ) {
      printf( "All alpha\n" ); 

    } else {
      printf( "Mixture.\n" ); 
    }
  }

  return 0; 
}