Thread: Help with a 2D Array in C

I have been working on a 8x8 Array for a day or two, and this what I have

Code:

#include <stdio.h>
int main()
{


  int  x,y;


  for(y=1;y<=8;y++){
    for(x=1;x<=8;x++){
      int Board[8][8];


 printf(" %d", Board[8][8]);
    }
        printf("\n");
  }


  return 0;
}

But instead of getting a 1-8 count in columns and rows, all i get is zeros like this:

Code:

 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0

please help me understand how to get a true 8X8 matrix

ps
I am not looking for the answer, only the way to it....

You need to initialize your array at the top below main, not inside your for loop. Right now you are not changing the value of your array or the indexing of it. Look at how you have hardcoded the indexes. Instead of that you can use x and y representing your rows and columns. P.S. You should start x and y off at 0 and < 8 .

First , Thank You.
Do you mean like this:

Code:

#include <stdio.h>
int main()
{


  int  x,y;
  int Board[y][x];
  for(y=1;y<=8;y++){
    for(x=1;x<=8;x++){
 printf(" %d", Board[8][8]);
    }
        printf("\n");
  }


  return 0;
}

if so, I get the same results..

Few things:
1. You are fine with the hard coding in your initialization of int board[8][8].
2. Your for loop should start at 0 and go to < 8, for(x=0;x<8... same for y. In C arrays start indexing at 0.
3. You also need to display using your x and y indexes. printf(... board[x][y].

You havnt given any actual values to your array so you will find that it will be a bunch of random numbers when you do print it.

Code:

for(r=0;r<8;r++) {
   for(c=0;c<8;c++) {
      board[r][c]= r;
   }
}

for(r=0;r<8;r++) {
   for(c=0;c<8;c++) {
      printf("%d ",board[r][c]);
   }
   printf("\n");
}