Thread: Error that does not make sense.

I'm getting an error from comparing a character pointer and an integer.

Heres some code.


char *scan_array = &word[0];
char letter;

while(scan_array != letter) // This is the line with the error.


I dont understand why I'm getting this error when 'letter' is a character.

But scan_array is a pointer. Perhaps you should use while (*scan_array != letter) which dereferences the pointer and uses the char (element [0] of word array).

*scan_array or *scan_array[number] or *scan_array+number - you can access the value of that address
scan_array - is a pointer variable

Well, all I needed is the asterisk. Wow, I don't understand why it was giving me that error.
But it is fixed, Thanks for the help!

I don't understand why it was giving me that error

A "char" is really just a differently sized integer, though I'm also surprised it bothered to tell you the specific type of pointer but not the specific type of variable.

Ok, that does make sense. Haha just confusing at first.

Originally Posted by amzc

*scan_array or *scan_array[number] or *scan_array+number - you can access the value of that address

Your second and third suggestion is wrong. Do you know why?

Bye, Andreas

I also hope letter is actually initialized with something sane.