Thread: Problem with printing float precision values.

The code bellow is going to print a value with 12 digits precision

Code:

#include <stdio.h>

int main(void)
{
   double c, xc=50800.287F, w, f=125000.0F;
   w=2*3.14*f;
   c=1/w*xc;

   printf("capacitance value is : %.12f\n", c);

   return 0;
}

Are you sure that double is not supported?I mean it is a primitive type of C.... What error do you get?

EDIT : Ok, i think you have a logical error.
What you want is

Code:

c=1/(w*xc);

but you have

Code:

c=1/w*xc;

The problem is that in your code the code will be executed like this : (1/w)*xc

Mind also that you need at least 11 digits precision otherwise you will see only zeros.

And with a second thought i found out that float is ok.So i tried it...

Code:

#include <stdio.h>

int main(void)
{
   float c, xc=50800.287, w, f=125000.0;
   w=2*3.14*f;
   c=1/(w*xc);

   printf("capacitance value is : %.12f\n", c);

   return 0;
}

and the output was

Code:

Macintosh-c8bcc88e5669-9:~ usi$ ./px
capacitance value is : 0.000000000025
Macintosh-c8bcc88e5669-9:~ usi$

Hope this helps