Thread: simple matrix

Thanks its working

Code:

#include<stdio.h>
#include <stdlib.h>

int main (void)
{
  int row_size1,col_size1,row_size2,col_size2,flag =1;
  int **A;
  int i = 0, j = 0;
  char a,c;

do
  {
    printf("\ncmd> ");
    c = getchar();

if(c == 'A')
      {

scanf("%d %d",&row_size1,&col_size1);

A= malloc(row_size1*sizeof(int*));
  for(i=0;i<row_size1;i++)
    {
      A[i]=malloc(col_size1*sizeof(int));
    }

for(i=0;i<row_size1;i++)
    {
     for(j=0;j<col_size1;j++)
        {
          scanf("%d",&A[i][j]);
          if (A[i][j] == 99) // 'x' is character variable i declared
            break;
        }
    }

printf("The required matrix is\n");
  for(i=0;i<row_size1;i++)
    {
      for(j=0;j<col_size1;j++)
      printf("%d ",A[i][j]);
      printf("\n");
    }
  

for(i=0;i<row_size1;i++)
    {
free(A[i]);
    }
  free(A);
      }
  }
 while(flag == 1);
 return 0;
}

And the crowd goes wild!