Thread: Scanf inside IF statement not working

This is the code, after i enter age:60+ , it goes straight to the output and doesnt execute th scanf inside, thanks for the help

Code:

#include<stdio.h>
int main(void)
{
    int age;
    char sts;
    printf("Enter the age: \n");
    scanf("%d", &age);
    
    if(age>59)
        {
        printf("Enter W for working or R for retired: \n");
        scanf("%c", &sts);
            if(sts=='W')
                printf("Working senior\n");
            else
                printf("Retired Senior\n");
        }
    else if(age>20)
        printf("Adult \n");
    else if(age>12)
        printf("Teen \n");
    else
        printf("Child \n");
    return 0;
}

Originally Posted by ace88

This is the code, after i enter age:60+ , it goes straight to the output and doesnt execute th scanf inside, thanks for the help

Code:

#include<stdio.h>
int main(void)
{
    int age;
    char sts;
    printf("Enter the age: \n");
    scanf("%d", &age);
    
    if(age>59)
        {
        printf("Enter W for working or R for retired: \n");
        scanf(" %c", &sts);
            if(sts=='W')
                printf("Working senior\n");
            else
                printf("Retired Senior\n");
        }
    else if(age>20)
        printf("Adult \n");
    else if(age>12)
        printf("Teen \n");
    else
        printf("Child \n");
    return 0;
}

now it should work

What root wants to say is :
When you enter the age think of the events happening in your keyboard.You tupe 61 for example and then you hit enter.So the buffer where the data from stdin is stored to , in order your program to handle this data contains the number and the \n (newline character).
So you read the number with

Code:

scanf("%d", &age);

And then you have another scanf which is going to consider as input given the newline that was left by your first input .
So you write

Code:

scanf(" %c", &sts);

, so that scanf skips the newline.(What you have to do is leave a space before %c)

I see, thanks to both of you.