The assignment wants me to print the value and the address of a and b, i dont know why I am having so much trouble with this it seems simple, i just need some direction.
Code:#include <stdio.h> void print_info(int a, int *b); int main(void) { int x; printf("Enter a value for x: "); scanf("%d", &x); print_info(x, &x); return 0; } void print_info(int a, int *b) { printf("%d", a); printf("%p", &a); printf("%d", *b); printf("%p", b); }
My guess is that your "trouble" concerns the variable a inside print_info(). You will find that &a inside print_info() will have a different address from b (since a is passed by value, it becomes a variable with the same value as x, but at a different location in memory). So the two values produced using %d will be the same, but the two addresses formatted using %p will differ.
For future reference, it would have helped if you actually described what you meant by "so much trouble". Forum members are not mindreaders, you know, and forcing people to guess what your problem is is not an effective way of getting help. Most forum members will simply not bother to help. The only reason you got a response from me is that I happened - by accident - to be able to make a guess quickly.
In particular, you should have described what output are you expected your code to produce, and provided an example if the output differs from your expectations.
Yep that program looks fine to me also.
I too believe that the problem is with your expectations.
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Well I am pretty sleep deprived right now, but I am pretty sure that the int on line 3 should not be there. Can you give a bit more info on your actual problem?
That "int" on line 3 can be left out (it's optional in C) but doing so is often considered to be bad practice.Originally Posted by Codegeek892
That "int" on line 3 is sometimes (often) written as the beginning of line 4, before what is already there
Code:int main(void)
