Thread: Can't find the error

Hello guys. Here's my code. I want to average the numbers entered by the user.

Code:

#include<stdio.h>
#include<ctype.h>


int main(void)
{
	int value = 0;
	char answer = 'n';
	int total = 0;
	int count = 0;


	for( ;; ) {


		printf("Enter a value: ");
		scanf("%d", &value);
		total += value;
		count++;


		printf("Continue?(y/n): ");    
		scanf("%c", &answer);   // this code is getting skipped
		
		if(tolower(answer) == 'n') 	
			break;
	}


	printf("Avg. is %d", total/count);


	return 0;
}

Thanks in advance.
--Sid

Change the line to

Code:

scanf(" %c", &answer);   // this code is getting skipped

Print the value (and character) of the answer to the second question:

Code:

        printf("Continue?(y/n): ");   
        scanf("%c", &answer);
        printf("you answered with the character with value %d ('%c')\n", answer, answer);

Code:

scanf(" %c", &answer);   // this code is getting skipped

That's totally amazing for me. Could you tell me the reason behind that.

Thank You very much rags_to_riches and qny

This is one of the most frequently asked questions here.

The new line character generated by hitting the enter key is still in the input buffer. The space before the %c ignores any whitespace (like a new line) in the buffer.

So this happens only with the %c specifier if I got it right. Am i correct?

All scanf() specifiers except "%c", possibly "%[...]", and (for very different reasons) "%n" ignore leading whitespace.