Thread: Too few arguments error. Calling a function from within a function?

Here

Code:

double calc_baking_time(char bread_type, char loaf, char manual);

you declare your function to take three arguments.

Here

Code:

calc_baking_time();

you call it without any arguments.

What do you not understand when the compiler tells you that you use "too few arguments"?

Bye, Andreas

Originally Posted by AndiPersti

Here

Code:

double calc_baking_time(char bread_type, char loaf, char manual);

you declare your function to take three arguments.

Here

Code:

calc_baking_time();

you call it without any arguments.

What do you not understand when the compiler tells you that you use "too few arguments"?

Bye, Andreas

0.0. i updated the OP. Thanks for catching my mistake

1. Don't edit the original post like that - it makes the subsequent responses confusing.
2. There don't seem to be any values being passed to your function - you might want to declare those as variables, define them, then pass them to the function.
3. When you call a function, you aren't supposed to include the data types like that. Did you try compiling that code? What happened?

Code:

int sum(int x, int y);  // <-- function declaration/prototype

int main(void)
{
    int result;
    int a = 3;
    int b = 4;

    result = sum(a,b);  // <-- function call (from within "main()")

    return 0;
}

int sum(int x, int y)   // <-- function definition
{
    return (x + y);
}

Calling a function from a function is the same as calling a function from "main()" (which is, after all, another function).