Thread: POW() func giving weird output

Hi everyone,

I ran into problems with the pow() function in my main program so I isolated the problem in another c file to test out but I am still not sure what could be wrong.

Code:

#include <stdio.h>
#include <malloc.h>
#include <string.h>
#include <stdlib.h>
#include <math.h>

int main(int argc, char **argv) {
  int i = atoi(*(++argv));
  int d = atoi(*(++argv));
  printf("%d^%d=%d\n",i,d,pow(i,d));
  // the output of this is i^d=i, not sure why
}

As noted in the comments but the pow() function is not working correctly and I am already using the -lm option because I am using gcc.

I get the above output of i^d=i for any combination of i and d. Any idea what could be wrong?

pow function returns a double or other non-int types pow - C++ Reference
In your printf you use %d to print the result while you should use %f for a double.

PS-run your code after removing the malloc.h (gcc won't recognize it)

PS2- it is not only because gcc.Maybe you are on linux.I used gcc and did not have to use it

Ah ok. I thought this might be the cause of the problem in my other program but I guess it probably isn't. Thanks for the help. The other includes were for my other program which is why they were here.

Originally Posted by workisnotfun

Ah ok. I thought this might be the cause of the problem in my other program but I guess it probably isn't. Thanks for the help. The other includes were for my other program which is why they were here.

Glad that helped Good luck with the project~!