Thread: Explanation for working of (char *) type syntax

It feel bad but I got stuck with a noobish type syntax, need explanation.

Code:

LPARAM name; //have a pre defined value
LPARAM length; //have a pre defined value
fgetws((wchar_t *)name,length,stdin); //need explanation
wchar_t *ptr=wcspbrk((wchar_t *)name,L"\r\n"); //explanation

Its actually the part of a another large code. here 'name' and 'length' will get values at the time of calling. So don't worry about their values.
Do explain how this small code works here.

And how to send another value to 'name' as it is given by fgetws().???

Thanks in advance.

Originally Posted by ledow

LPARAM is a pointer.

"name" is of type LPARAM.

"(wchar_t *) name" casts name to a pointer to a (wide, i.e. Unicode) string.

The fgetws gets a wide string of length "length", from stdin, and put it into that string.

You can do the last line on your own now if I tell you that "\r\n" is a carriage-return and line-feed and you can lookup wcspbrk online.

Well in that case...
Are the two below lines results into similar output.??

Code:

fgetws((wchar_t *)name,length,stdin); //with input of 123

and

Code:

(wchar_t *)name=L"123";

If not.. then how to pass the value "123" to the (wchar_t *)name through code(manually instead of keyboard) which results to similar output as it is done by fgetws() function.???

and Thanks for your explanation. It is crystal clear.

Originally Posted by Codeplug

Code:

wcscpy((wchar_t*)name, L"123);

gg

Thanks