Multiplication of odd or even integers according to user selection.

[motaro15]

Greetings,

I've been fighting with this program for some hours now, and there are so many things the program is requesting that I'm overwhelmed, I was wondering if anybody can point me in the right direction.

I need a program that will calculate products based on user command (1 or 0), the user will select a number before this so that it can become the last number to be multiplied.

If user inputs 0, calculate: 1*3*5*…*n (n is an odd number picked by the user)

or 1*3*5*…*(n-1) (n is an even number picked by the user);

If user input 1, calculate: 2*4*6*…*(n-1) (n is an odd number picked by the user)
or 2*4*6*…*n (n is an even number picked by the user).

So far I got...

#include<stdio.h>

int main()
{
    int n;
    int command;
    int result;
    int usernumber= 0;


    printf("Please input a positive integer:");
    scanf("%d", &n);


    printf("Please input the command for computation of products:");
    scanf("%d", &command );


    If (command == 1, usernumber++){
        do{
        printf( "%d", result);
        }
        while( nums > n )
    }


}

Please halp D:

[laserlight]

You probably should be using a for loop. Note that keywords and names are case sensitive, so If and if are not the same.

[motaro15]

Good observation, I didn't even notice hehe. Thanks for your help, I'll keep working on this monster.

[Click_here]

If you are still having trouble after you put in a 'for' loop, post your new code.