strncpy. Need help.

[wacky_jay]

How can I get the "not to" string and removing the "To be or" and the last "be"? What should I do?

#include<stdio.h>
#include<conio.h>
#include<string.h>
int main(void)
{
  char str1[]= "To be or not to be";
char str2[6];
strncpy (str2,str1,5);
  str2[5]='\0';
  puts (str2);
getch();
return 0;
}

[qny]

Your str2 array has enough space for 6 characters (or a string with length 5).
You are copying 10 characters into it.
Lucky you: your computer didn't explode

char str2[7]; /* just enough space for the string "not to" */
strncpy(str2, "To be or not to be" + 9, 6);
str2[6] = '\0';

[wacky_jay]

Sorry qny, I edited the code. hehe.

[std10093]

In my mind this seems much more easy (look at the comments)

#include <stdio.h>

int main(void)
{
    char* str= "To be or not to be";
    char result[7];/*7 because of the null terminator*/
    int i;

    /*skip characters until you find n*/
    while(*str != 'n')
    {
        *str++;
    }
    /*copy the requested string*/
    for( i = 0 ; i < 6 ; i++)
    {
        result[i] = *str++;
    }
    /*do NOT forget the null terminator*/
    result[6] = '\0';
    printf("Result is %s \n",result);
    return 0;
}

I could have declared result as a pointer to and then allocate memory with malloc

[wacky_jay]

Thanks qny! I finally got it.