Thread: Error with my function

  1. #1
    Registered User
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    Aug 2012
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    Talking Error with my function

    Here is my function:
    Code:
     
    void Display_Info(clock_num,  wage_rate, clock_hours,  overtime_hours,  gross_pay)
    {
        int count;     /* Variable used for loop counter */
    
        /* Create table to display employee information */
            printf("\n------------------------------------------------\n");
            printf("Clock#      Wage     Hours     OT      Gross\n");
            printf("------------------------------------------------\n\n");
    
            /* print employee information from arrays into table */
            for (count = 0; count < SIZE; count++)
                printf("%06li     %5.2f    %5.1f   %5.1f    %7.2f\n", clock_num[count] , wage_rate[count] , clock_hours[count] , overtime_hours[count],  gross_pay[count]);
    }
    and here is my call within main
    Code:
     
    Display_Info(clock_num, wage_rate, clock_hours, overtime_hours, gross_pay);
    I am getting subscripted value is neither an array or pointer on line 12. I am not sure what to do and as per directions, I am not to use pointers. How can I fix this?
    Last edited by rpmischris; 10-01-2012 at 10:47 PM.

  2. #2
    Algorithm Dissector iMalc's Avatar
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    You are missing the parameter types. You should be getting warnings about that.
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  3. #3
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    Quote Originally Posted by iMalc View Post
    You are missing the parameter types. You should be getting warnings about that.
    lol what does that mean?

  4. #4
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    lol nevermind.. I just had a severe brain fart.

  5. #5
    Registered User poornaMoksha's Avatar
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    Code:
    void Display_Info(clock_num,  wage_rate, clock_hours,  overtime_hours,  gross_pay)
    You need to mention the types for all the function parameters in here. Otherwise default types would be assumed by the compiler and probably thats causing the trouble.

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