Thread: Using functions with pointer arguments - Connect 4

Code:

if(sqr % COLS==0 && sqr)
         printf("\n");

Just checks if sqr value is a multiple of COLS, and sqr is non zero -- if so, print out a newline char so we have another row to display on.

I'm running into trouble again
This time I'm attempting to store the lowest row value of the columns to an int array, so I can keep track of the next piece dropped into that column. Here is my test code for the first column (since I'm dealing with a single array of length 42, the first column starts at position 0 and ends at 35, with 7 unit increment each time):

Code:

int top[7]; //declaring the array that will holds the position
				//of the lowest empty row of each column
	// printf("size is: %d \n", sizeof(top));
	// printf("first element is: %d \n", top[0]);
	int top_0;
	for (top_0 = 35; top_0 >= 0; top_0-=7){
		if (grid[top_0] != '-') {
			top_0+=7;
			top[0] = top_0;
			break;
		}
	}

I'm looping through the 6 rows of the first column starting at index 35 (the highest position), with a decrement of 7 each time. If a slot is found to be occupied, then the lowest empty row is right above it, so I would return that index + 7. That number will finally be assigned to the first index of the int array top, which is top[0]. I tried to compile it but it didn't work. Thanks for your help in advance guys !

Originally Posted by Thinh Cao

I tried to compile it but it didn't work.

"didn't work" is not a useful problem description. (I recommend reading How To Ask Questions The Smart Way)

What exactly didn't work? Did you get errors/warnings from the compiler? Did your program crash? Did you get an unexpected result?

Bye, Andreas