error: cannot convert from 'char [13]' to 'char [20]'

[Unregistered]

cannot convert from 'char [13]' to 'char [20]'

how do i fix this? my struct emp is:
struct employee
{
char name[20];
int id_number;
float wage;
float hours;
float overtime;
float gross;
};

and my data is:

emp[0].name ="Connie Cobol";
emp[1].name ="Mary Apl";
emp[2].name ="Frank Fortran";
emp[3].name ="Jeff Ada";
emp[4].name ="Anton Pascal";

I get the error pointing to all 5 of these lines...

[swoopy]

Try strcpy().

strcpy(emp[0].name, "Connie Cobol");
strcpy(emp[1].name, "Mary Apl)";
strcpy(emp[2].name, "Frank Fortran)";
strcpy(emp[3].name, "Jeff Ada)";
strcpy(emp[4].name, "Anton Pascal)";

[Unregistered]

when printing the data I can't get it to lone up properly because of the different lengths of the names. How can i make it display the names so that they will always be 20 spaces (name + spaces)

My printf looks like this:

printf ("%s %06i %5.2f %5.1f %5.1f %5.2f\n", emp[i].name, emp[i].id_number, emp[i].wage, emp[i].hours, emp[i].overtime, emp[i].gross);

[Magos]

You could try this:

strcpy(emp[1].name, "Mary Apl)";
TempSize=strlen(emp[1].name);
emp[1].name[TempSize]=' '; //Removes NULL terminating character
emp[1].name[19]='\0'; //Adds NULL terminating character

[quzah]

Use "%20s" to make all output of names a fixed 20 characters in length.

Quzah.

[Unregistered]

when i uaws the %20s it does fix them to 20 but it appends the extra spaces to the beginning. how do i make it so it appends the extra spaces to the end?

[swoopy]

How about?

%-20s

[Unregistered]

Thanks everyone. programs working perfect now.