Counting 1-50 and pointing out odd and even numbers

[juliette]

Hello!

I've just started an introduction course in C programming at the University. I am currently struggling on the last exercise of an mandatory assignment.

Its probably some basic stuff, but we were asked to make a program that counts from 1-50, which i have following code for;

#include <stdio.h>

int main(void)
{
int i;

for (i=0; i <= 50; i=i+1)


{printf("%d\n", i);
}

This code works just fine, but the follow-up question is giving me a headache. We are asked to make the program to point out if the numbers are even or odd (with an "if" statement!).

Example:
1 is an odd number
2 is an even number
.... etc

Hope you are able to help

edit: Sorry about some misspellings, the assignment isnt given in english.

[root4]

It's not an 'if' "function", but an 'if' "statement", also called a conditional; you don't need any function.

[Salem]

Assuming that getting to university means you know about basic mathematical operations like division and remainder (modulus), the interesting operator for you to go and read about is %

[juliette]

I think I have the right code to state which of the numbers that are even or odd, but my problem is to add ".. is an even number" in the original code.

[root4]

Post what you have so far.