[warning] strcpy makes pointer from integer without a cast

[HandsThatHold]

Hi! I'm new to CBoard and to programming so please bear with me. Imma noob.

Suppose I have this structure for Costumer Account:

typedef struct
{
      char account[6];
      int balance;
}COSACC;

And I have to compare the balance from something inputted.

printf("\n\nEnter New Balance: ");
scanf("%d", &ab);
strcpy(y[i].balance, ab);

How do I do something like that as to not get a warning? Thanks so much!

[std10093]

Could you post more of your code please?
What is the y and ab declared as?
You get this warning because you do not pass the arguments as you should.You have to keep in mind the prototype of strcpy strcpy - C++ Reference.There is also an example there

[jimblumberg]

Since balance is an int not a C-string you would do something like:

y[i].balance = ab;
// or without the intermediate variable.
scanf("%d", &y[i].balance);

The strcpy() function only works with nul terminated character strings.


Jim

[whiteflags]

Just get rid of strcpy() altogether and compare the two integers in your code.

[iMalc]

They aren't strings, so all you probably wanted was:

y[i].balance = ab;

However, if that's all you're doing, then you don't need the variable ab at all. You could just read straight into the desired location, in two lines, like this:

printf("\n\nEnter New Balance: ");
scanf("%d", &y[i].balance);

[HandsThatHold]

They aren't strings, so all you probably wanted was:

y[i].balance = ab;

However, if that's all you're doing, then you don't need the variable ab at all. You could just read straight into the desired location, in two lines, like this:

printf("\n\nEnter New Balance: ");
scanf("%d", &y[i].balance);

Thank you! This was all I needed to do.

Sorry it took me this long to reply. I'm swamped with projects and darn tests. Thanks for all your help, guys!