Creating text file with random numbers

[l_l]

Hi,
I need to create a program that outputs a .txt file with a 20x30 array of random numbers from 0 to 9. What I have creates the .txt file, although it is empty when opened. Here is what I have:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(void)
{
    FILE *fp;
    int i, j;
    char list[20][30];
    
    if((fp = fopen("numbers.txt", "a+")) == NULL)
    {
        fprintf(stdout, "Can't open \"numbers\" file.\n");
        exit(1);
    }
    
    srand(time(NULL));                     //initialize random seed
        
    puts("the random numbers from 0 to 9 are:");    
    
    for (i=0; i<20; i++)
    {    
        for (j=0; j<30; j++)
        {
            list[i][j] = rand() % 10;        //random number between 0 and 9
            
            fprintf (stdout, "%d ", list[i][j]);
        }    
        
        putchar('\n');
    }
    
    if(fclose(fp) != 0)
    {
        fprintf(stderr,"Error closing file\n");
    } 
    
    return 0;
}

[Salem]

> fprintf (stdout, "%d ", list[i][j]);
Maybe printf to fp instead?

[std10093]

Your actually sending the data to stdout,and not the file itself!Don't you see them at your screen?

[l_l]

I see the data on screen, but I would like to see them in the file as well.

[std10093]

I see the data on screen, but I would like to see them in the file as well.

So you should do what salem said!fprintf send the data to the stream you told her to.So if you use stdout,the data will be printed on screen.If you use fp,then the data will be sent to where fp points(fp points to your file!)
So i you want to see them both in file and in screen ,use fprintf twice.Ok?

[l_l]

thanks for the help. I got it to work.