Thread: char**

  1. #1
    Registered User sean345's Avatar
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    Lightbulb char**

    I am trying to use a char** in my program, but my program crashes.

    First I use this:

    char** Line;

    FileSize = GetFileSize(hFile, NULL);
    Line = Memory(FileSize*sizeof(char*));

    Later in my program I use:

    strcpy(Line[CurLine], Buffer);

    This causes the program to crash. What is wrong here?
    If cities were built like software is built, the first woodpecker to come along would level civilization.
    Black Frog Studios

  2. #2
    ATH0 quzah's Avatar
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    char** Line;

    strcpy(Line[CurLine], Buffer);

    This causes the program to crash. What is wrong here?
    You're only allocating pointers not space. You're copying to some random pointer some place in memory. Allocate space for "Line[CurLine]" pointer then copy into it.

    Quzah.
    Hope is the first step on the road to disappointment.

  3. #3
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    I dont understand why your declaring a char **Line; if this is your declaration for your pointer then it should be simply char *Line

  4. #4
    ATH0 quzah's Avatar
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    I dont understand why your declaring a char **Line; if this is your declaration for your pointer then it should be simply char *Line
    Basicly they want an array of lines. Each line is a character pointer. Think of it like this:

    We have a text file. It has X number of lines in it. Each line is a different length (possibly) and we want to be memory-efficient.

    We create an array who's size is the exact size as the number of lines, then for each line, we allocate space for it, and read it into this line.

    His problem is that he just isn't allocating space for the line.

    Quzah.
    Hope is the first step on the road to disappointment.

  5. #5
    Registered User sean345's Avatar
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    Thanks

    Ok, Thanks for your help.
    If cities were built like software is built, the first woodpecker to come along would level civilization.
    Black Frog Studios

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