Thread: Reverse array by swapping

Hi,

In Below code

Code:

#include <stdio.h>
int main()
 {

  int array[100], n, c, t, end;
 
  scanf("%d", &n);//4 number iam giving as input

  end = n - 1;//end=3
 
  for (c = 0; c < n; c++) {

    scanf("%d", &array[c]);//arr[0]=2,arr[1]=3,arr[2]=4,arr[3]=5
  }
 
  for (c = 0; c < n/2; c++)
    {

    t          = array[c];
    array[c]   = array[end];
    array[end] = t;

//so for loop 

/*for(c=0;c<2;c++),it would be 

t=arr[0]         ==it would be t=2 as arr[0]=2
arr[0]=arr[3]    ==it would be arr[0]=5 
arr[3]=t         ==it would be arr[3]=2

so now arr[0]=5
       arr[3]=2
            

  
/*Now for second for loop

/*for(c=1;c<2;c++) it would be 

t=arr[1]          ==it would be t=3
arr[1]=arr[3]//iam stuck here ,whatz this arr[end] depicts whether it is arr[3] 
value or arr[2] value */   

  
  }
 
  printf("Reversed array elements are:\n");
 
  for (c = 0; c < n; c++) {
    printf("%d\n", array[c]);
  }
 getch();
  return 0;
}

i got stuck in second for loop as in comment