How can I get the size of a multidimensional int/char array?
If I have that as example.Code:int array[80][80]= {{1,2,3},{4,5,6,7},{8,9,10,11,12}};
How can I get it to return the actual size of the array, the inner arrays (not the outer)?
Using the normal sizeOf will return just the entire size of the array as I specified [80][80] but not the actual size of the arrays.
Code:int myLength = sizeof(array)/sizeof(int);
If you mean that, in your case, you want to compute the size of the array with elements 1,2,3 as 3 rather than 80, then you can't.
The compiler does not keep track of such information for you. You will need to keep track of the sizes manually (i.e. store the value 3 in some variable you can use).
Oh ok, than I think I know a good way to do it.
Can you btw generate or make them dynamically? After compilation, while it is running. Or is that also not possible?
C99 allows for variable length arrays: https://en.wikipedia.org/wiki/Variable-length_array
Quzah.
Hope is the first step on the road to disappointment.
And, if you don't want to use VLAs (eg your compiler is C89 compliant rather than C99 compliant) use dynamic memory allocation (malloc(), free(), etc). It takes a bit more work than one-dimensional arrays but, if you remember that a 2-dimensional array is an array of 1-dimensional arrays, it is not too hard.
