Thread: Picking random numbers from an array

Code:

Copy this code into your C program.

// Then complete the subroutine deal() below so that 5 cards are randomly assigned to cards[][]
// Each time the subroutine is called, a different hand should be dealt.
// There are 52 cards, 13 denominations, 1 in each of 4 suits.
// The cards, Ace-through-King, A,2,3,4,5,6,7,8,9,10,J,Q,K and four card suits Spades (S), Hearts (H),
//    Diamonds (D), and Clubs © are used to denote, e.g. a Jack of hearts as "JH",
//    and a 10 of diamonds as "10D". Use the array cards[][] in deal()


#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void deal(char *ptr);
main(){
int m;
char hand[5][4],nd;
int nodeal;
printf("deal a hand? (enter y or n) ");
scanf("%s",&nd);
while(nd=='y'){
deal(hand[0]); // hand is a pntr-to-a-pntr. hand[k] is a pntr.
for(m=0; m<5; m++){printf("%s ",(hand[m]));}
printf("\n");
printf("deal a hand? (enter y or n) ");
scanf("%s",&nd);
}

system("pause");
}

void deal(char *ptr){
char cards[52][4]={"AS","2S","3S","4S","5S","6S","7S","8S","9S","10S","JS","QS","KS","AH","2H","3H",
"4H","5H","6H","7H","8H","9H","10H","JH","QH","KH","AD","2D","3D","4D","5D","6D","7D","8D",
"9D", "10D","JD","QD","KD","AC","2C","3C","4C","5C","6C","7C","8C","9C","10C","JC","QC","KC"};
int i,j,k,c[5];



// seed the random numer generator using the time srand((unsigned int)time(NULL));


// generate 5 random values 0-to-51 with no duplications.

// check for duplications, correct any duplications

// load the chosen cards using the pointer. You’ll need to load 4 bytes/card based on the character pointer

}



Can anyone help me to complete this function. I am having a hard time doing it. 

First of all.

You should do something with the readability
of this code.

i.e ->

Code:

 for(m=0; m<5; m++){printf("%s ",(hand[m]));}

You can write it as ->

Code:

 for(m=0; m<5; m++)
     printf("%s" , (hand[m]));

if the body of the loop contains only one command there is no need to add some braces.