Thread: How to print number of characters per line

Originally Posted by QuantumPete

%c prints a char, not a string. For strings you need to pass a char pointer and use %s

To be fair, I did mention this above too: "You also want to print a STRING, not a char,"

But good to see that the program's progressing nicely. When this thread started you didn't "have any idea", "cant figure it out", etc. and now you're 99% of the way to finishing the thing. And how much did we actually have to do for you? Virtually zero.

Keep going.

Originally Posted by ledow

To be fair, I did mention this above too: "You also want to print a STRING, not a char,"

But good to see that the program's progressing nicely. When this thread started you didn't "have any idea", "cant figure it out", etc. and now you're 99% of the way to finishing the thing. And how much did we actually have to do for you? Virtually zero.

Keep going.

Yes, I too am amazed by the sudden burst of determination. As long as he didn't copy it from somewhere, which does not seem to be the case, kudos.

Originally Posted by Slyvester Ping

If I have a variable result,which is "number_of_char_per_line/number_of_array_per_line", and I wan to printf("%(result)s ",word),how can i do it? I cant just put the result in there,I will print out result,but I want the integer stored in the variable result.

Eh?

Originally Posted by Slyvester Ping

Will it be better for understanding if I show my code?

Yes.

Oh, hold on. You mean:

You want to print a number in the middle of a printf statement? Yes?

Assuming "number" is an integer:

Code:

printf("The next thing is your number %i and nothing else", number);

There are other "%whatever's" that indicate unsigned integers, floats, strings, etc. so you can do something like this:

Code:

int number1 = 0;
int number2 = 0;
char *string1 = "Fred"

printf("This is the first integer %i, this is the second %i, and this is a string %s", number1, number2, string1);

You could read the man page.

Code:

Field Width:
	     An optional digit string specifying a field width; if the output
	     string has fewer characters than the field width it will be
	     blank-padded on the left (or right, if the left-adjustment indi-
	     cator has been given) to make up the field width (note that a
	     leading zero is a flag, but an embedded zero is part of a field
	     width);

A field width or precision may be `*' instead of a digit string.  In this
     case an argument supplies the field width or precision.

Quzah.

Originally Posted by seemaxie

HI slyvester,

why dont you try functions getchar() and putchar().. your assignment is is easily achievable with this functions.. while you have to include ctype.h header... which eventually helps you to understand strings in better...Playing around with strings really need some programming experience ..

Code mite look like this

Code:

#include <stdio.h>
#include <ctype.h>
char ch;
 while(( ch=getchar() )!= 'q')
     {
implement New line for every 20th character

print ch

}

Donny..... please.

Generally I think the easiest way to do it is using the information quzah provided.

As for your code, one obvious problem you are having, and is generally a problem with getchar() is that when you input a character you automatically feed the input buffer 2 characters(the one you typed and the return key), so you need another getchar() immediately after to discard the second.

To be honest, there have been very few times, if any, when I thought to myself "getchar" may be of great help here, so I generally steer clear of it.