Thread: How to print time in yyyy:mm:dd format?

I know it has something to do with time.h, but I'm not familiar with using that header's functions. Right now I have:

Code:

    time_t TimeNow = time(NULL);
    struct tm *tm = localtime(&TimeNow);
    printf("%d:%d:%d", tm->tm_year, tm->tm_mon, tm->tm_mday);

It compiles, but it gives me this:

112:2:25

The month and day make sense, but they're lacking the preceding 0s. The year just doesn't make any sense.

This works, but is this good, syntax-wise?

Code:

time_t t;    struct tm* tm;
    char Date[11], Time[11];
    
    time(&t);
    tm = localtime(&t);
    
    strftime(Date, sizeof Date, "%Y:%m:%d", tm);
    strftime(Time, sizeof Time, "%I:%M:%S", tm);
    printf("%s ", Date);
    printf("%s", Time);