Thread: intialise 2D arrays??

This works fine:

Code:

#include <stdio.h>
#include <conio.h>

const int Width=5;
const int Height=8;

int MyArray[Width][Height]={0};

void Func(int Array[Width][Height])
{
   Array[0][0]=12345;
}

int main()
{
   Func(MyArray);
   printf("%d", MyArray[0][0]);
   getch();
}

Originally posted by Unregistered
so instead of defining the width and height ourselves

can we have user define it through scanf ?

Yes, but not in this way. We must use dynamic allocation (new or malloc).

Sample (creates an int array with 10 elements):

Code:

int NrOfElements=10; //You can make the user input this number
int* Pointer;
Pointer = new int[NrOfElements]; //Allocate memory
if(Pointer!=NULL) //Check to see if allocation was successful
{
   //Do whatever you want here
   ...
   delete[] Pointer; //You must free the memory before you quit, memory leaks will occur otherwise
}

Originally posted by Magos

Yes, but not in this way. We must use dynamic allocation (new or malloc).

Sample (creates an int array with 10 elements):

Code:

int NrOfElements=10; //You can make the user input this number
int* Pointer;
Pointer = new int[NrOfElements]; //Allocate memory
if(Pointer!=NULL) //Check to see if allocation was successful
{
   //Do whatever you want here
   ...
   delete[] Pointer; //You must free the memory before you quit, memory leaks will occur otherwise
}

'new' and 'delete' are C++ keywords and they have no function in C. What you would want to do in C is this:

Code:

char **new2DCharArray( int x, int y )
{
    char **c = NULL;

    if( x > 0 && y > 0 ) c = malloc( x * y * sizeof( char ) );
    return c;
}

Quzah.

Originally posted by quzah


'new' and 'delete' are C++ keywords and they have no function in C. What you would want to do in C is this:
Quzah.

Oops, this is the C forum, right
My mistake...