Thread: Questions to Structure - Beginner needs help!

Handling hyphens, I can help you with, but debug mode, German code, and umlauts - no way.

If you have code to handle the ... as a word already, good deal.

Sorry again. Here is it in English:

Code:

// if(list[i-1].word[i]!='0'){
while((list[i].word[len]==' ') || (list[i].word[len]=='.') || (list[i].word[len]=='!') || (list[i].word[len]=='?') || (list[i].word[len]==',') || (list[i].word[len]==';') || (list[i].word[len]=='-') || (list[i].word[len]=='_') || (list[i].word[len]==':') || (list[i].word[len]=='\0') || (list[i].word[len]=='\n') || (list[i].word[len]=='\x0A') || (list[i].word[len]=='\x0D'))
                    {
                        list[i].word[len--]='\0';
                    }
// }

Originally Posted by Fresa

Sorry again. Here is it in English:

If it works, that's all that matters. There are always more than one way to do any specific thing, in programming.

If ... is a word - and you want all the words to be shown, don't you want the ... to be shown?

It will look odd if you want to number the ... as a word, but then don't show it in the word list, won't it? It will look like the program skipped a number, in the word count.

For example, with the ... as the third word, Edelweiss.txt listing would become:

1. Edelweiss
2. every
( not shown: 3. ... )
4. morning
5. you

New info: my teacher told me, that it has to work in the debug-mode. Yesterday my program works, but now it works JUST in the release-mode. I can't find the mistake. But I will restart at the last step, where it runs.

The three points must not been accepted as a word! So they sholdn't been shown. What did you change? Just this thing?:

Code:

while(!isalpha(list[i].word[len]) && list[i].word[len-2] != '.') {          list[i].word[len--]= '\0';          ++j;       }

Okay, I want to try it again, when my program runs again!
Do you have a solution, that "two,words" is shown as two words and not list as one word? Try this in a text-file:

two,words and-three-words

"two,words", is not a word. And it is not two words. It's just letters, a comma, and more letters, forming junk. Words are ended in English with either:

1) a space
2) a period, followed by a space or an end of the text (an EOF in our case).
3) a punctuation mark and a newline
4) a newline.

You can delimit junk like "two,words", if you like, but it's not English. That gets troublesome though with the logic we have already.

What;else:will,we%need&^to@accept!As=English?

Yes of course. Normally there is a space behind a comma. But I have to attend to typing errors. So if there is something like this (two,words) in the text it has to been shown as
two 1
words 1

and not as

two,words 1

The same for and-three-words.

I tried your proposition with "&& list[i].word[len-2] != '.'" again and I got this:
... 1
a 1
abcde 1

(and so on)

Without your addition it looks like this:
(here is a gap) 1
a 1
abcd 1

(and so on)

And now, there are just the points shown, but they must not been in the list!! This applys for all following special sings: . , - : ; _ ! ? (and blank space).

Are you shure, that you made blank spaces around this three points? Why doesn't work it with my program? Phew...!!

Another try (the program reads one line and then it goes through the line: sign by sign). But it prints out just rubbish:

Code:

#include <stdio.h>
#include <string.h>
  
struct alist{
    char word[26];
    int count;
};

int main(void)
{
    FILE *fp;
    int i=1, j=1, p=1, w=1, len, total;
    char puffer[100], *ret, c='\0';
    struct alist list[600];

    if((fp=fopen("test.txt","r+")) == NULL)
    {
        printf("ERROR\n");
    }
    else
    {
        while((ret=fgets(buffer, 100, fp)) != NULL)
        {
            while((c=fgetc(fp)) != EOF)
            {
                c=list[i].word[w];
                w++;

                if(c=' ') i++;
            }
        }
            
        for(i=0;i<=w;i++) printf("%s",list[i].word);

        fclose(fp);
    }
  
    fflush(stdin);
    getchar();
    return 0;
}

Thank's for your answers!

@Codeplug: I'm from Germany, so my teacher gave me a German text. Didn't you notice that in cause of my grammar and expressions?

But I found another way to resolve the umlauts-problem (this was tooo easy):

Code:

if(c=='Ä') c=142;
            if(c=='ä') c=132;
            if(c=='Ö') c=153;
            if(c=='ö') c=148;
            if(c=='Ü') c=154;
            if(c=='ü') c=129;
            if(c=='ß') c=225;

I don't understand the problem with the German text. What do you mean with "subject of locaes"?

I changed my program completely. Now it reads the document sign by sign.

Thank you all for helping me! You helped me a lot to learn and understand c-programming better. If I get more questions in the next parts of my task I will write again. Sorry, that I wasn't online regulary last week!