break not working in a function within a switch

[edsoneicc]

Hi. I am getting the 'break not working in a function within a switch or loop' error under someFunction(). My code looks something like this

do
{
    switch(choice)
    {
        case 1: if(a==1)
                {
                    someFunction(derp1, derp2, derp3);
            }
    }
}

Why does it say that the break; is not within a switch when someFunction is within a switch? How do I fix this?

void someFunction(int derp1, int derp2, int derp3)
{
    if(derp1==1)
    {
        /*blah blah blah*/
        break;
    }
}

[GReaper]

break doesn't propagate outside of functions.

[TheBigH]

Why does it say that the break; is not within a switch when someFunction is within a switch?

No. The nature of functions is that statements in them can't "see outside". The break inside someFunction simply does not know about how someFunction was called and has no way of knowing that someFunction was called from inside a switch.

[edsoneicc]

Oh I see. Thanks. I think I should just call the function again to 'break out'.

[MK27]

Oh I see. Thanks. I think I should just call the function again to 'break out'.

You could also use the return value of the function in the switch; currently it is void but you could use:

    if(derp1==1)
    {
        /*blah blah blah*/
        return -1;
    } else return 0;

In the switch:

        case 1: if(a==1)
                {
                    int x = someFunction(derp1, derp2, derp3);
                    if (x == -1) break;
            }