Thread: Logic Gates - Multiplexer Help

Hi, I have to make a 2:1 multiplexer in C programming for an assignment

The user has to input A B & C (with C being the switcher)

Y is the output

Truth table

C	A	B	Y
0	0	0	0
0	0	1	0
0	1	0	1
0	1	1	1
1	0	0	0
1	0	1	1
1	1	0	0
1	1	1	1

**Updated the truth table, since I ..........ed up the first one



Like the image above but, S = C

We have to make it out of standard gates, (AND, OR, NOT etc)

I have done this so far, it has no errors (but doesn't return the correct numbers - BIG ERROR)

Code:

#include<stdio.h>int And1(int a, int b);
int And2(int b, int c);
int Not(int c);
int Or (int And1, int And2);


int main (void)
{
    int a;
    int b;
    int c;


printf("\nEnter Value for A: ");
scanf("%i", &a);


printf("\nEnter Value for B: ");
scanf("%i", &b);


printf("\nEnter Value for C: ");
scanf("%i", &c);




printf("\n\nValue from Multiplexer = %d", Or);
system("PAUSE"); 
return 0;
}
int Not(int c)
{
    int output;
if(c==0)
output=1;
else
output=0;
return (output);
}
int And1(int a, int Not)
{
int output;
 if(a==1 && Not==1)
  output=1;
else
  output=0;
 return (output);
}
int And2(int b, int c)
{
int output;
if (b==0 && c==0)
 output=0;
if (b==0 && c==1)
 output=0;
if(b==1 && c==0)
 output=0;
if(b==1 && c==1)
 output=1;
return (output);
}
int Or(int And1, int And2)
{
int output;
if(And1==0 && And2==0)
 output=0;
if(And1==1 && And2==0)
 output=1;
if(And1==0 && And2==1)
 output=1;
if(And1==1 && And2==1)
 output=1;
return (output);
}

Any help would be much appreciated, I have looked on numerous forums and can find nothing that matches this