Code:
void get_day(int y,char* m,int d,int lp)
{
int c,a,i,cnt=0,b,e,sum,res,z;
int cent[10]={4,2,0,6,4,2,0,6,4,2};
int month_code[12]={0,3,3,6,1,4,6,2,5,0,3,5};
char month[12][5]={"jan","feb","mar","apr","may","jun","july","aug","sept","oct","nov","dec"};
char day[7][10]={"sunday","monday","tuesday","wednesday","thursday","friday","saturday"};
z=y/100;
b=y%100; //year
c=b/4;
for(i=17;i<=26;i++)
{
if(i==z)
a=cent[cnt]; //century
else
cnt++;
}
printf("a=%d\n",a);
printf("b=%d\n",b);
printf("c=%d\n",c);
printf("d=%d\n",d);
/*if(lp==TRUE)
{
if(*m=='jan')
e=6;
else if(*m=='feb')
} e=2;
else
{*/
for(i=0;i<12;i++)
{
if(strcmp(month[i],m)) //problem part
{
printf("val of i=%d\n",i); //test
e=month_code[i];
break;
}
}
//}
printf("e=%d\n",e);
sum=a+b+c+d+e;
res=sum%7;
printf("sum=%d\n",sum);
printf("res=%d\n",res);
printf("The day is %s\n",day[res]);
}
int leap_year(int year)
{
if(year%400==FALSE && year%100!=FALSE || year%4==FALSE)
return TRUE;
else
return FALSE;
}