Hey there. I seem to be having some syntax errors with this part of my code. I am new to this and I cannot figure out what is wrong. I am not sure if you need the whole code or just this part, but any help would be much appreciated.
Code:else { while(y<size) { while(x<size) { if((y=0) && (y=size-1)); { printf("*"); } else { if((x=0) && (x=size-1)); { printf("*"); } } else { printf(" "); x++; y++; } } } }
One problem I see is that you use the assignment operator in your if statements instead of the equality operator == .
Edit: also on line 8, you have else { if... } followed by another else. Use else if { ... } instead.
Last edited by Subsonics; 02-07-2012 at 02:36 PM.
Oh, thanks for noticing that. It probably is an issue, but that is not the one that I am currently frustrated with. I went and changed to the equality operators, but I still got syntax errors with the else statements.
And you have semi-colons after the ifs, making them pointless.
And here is what your program looks like properly formatted:
Maybe that will help you see the issue.Code:else { while(y<size) { while(x<size) { if((y=0) && (y=size-1)); { printf("*"); } else { if((x=0) && (x=size-1)); { printf("*"); } } else { printf(" "); x++; y++; } } } }
Last edited by rags_to_riches; 02-07-2012 at 02:40 PM.
Oh. Thanks rags. The semi-colons were the main issues with the last two syntax errors. But the very first syntax error with the else still remains.
You two else statements.
Well this is how far I have gotten with all your help. It is just syntax errors with the {'s. Lines 6 and 7, as well as the second to last }. How would I fix this? Thanks.
Code:else { while(y<size) { while(x<size) { if((y=0) == (y=size-1)) { printf("*"); } else if { ((x=0) == (x=size-1)) { printf("*"); } else { if((x!=0) == (x!=size-1)){ printf(" "); x++; y++; } } } } } }
Last edited by heyitsmeehd; 02-07-2012 at 03:32 PM.
