Thread: writing an fprintf statement toa file as text

Double your % - so %%e.

Do you literally want to write this in it's entirety?

Code:

fprintf(of "AC\nGain=%e\nPhase=%e\nUGF=%e\n\n", Gain, x, ugf)

If so why was, Gain, x and ugf's values printed? Do you think you could post some code, I don't really know what you are trying to do.

@Adak Thanks the double % worked!! :)

@subsonic yes I wanted that line to be printed literally and the values printed were not the values of the variables but were some garbage values.

Gaurav.

Yeah, the trick then is that you need to escape all special characters. I guess I was confused by the fact that your variables and new lines where printed. Still don't know what you did, can you post some code?

Code:

#include <stdio.h>

#define FPRINTF_STRING "fprintf(of \"AC\\nGain=\%e\\nPhase=\%e\\nUGF=\%e\\n\\n\", Gain, x, ugf)"

int main()
{
    printf("%s\n", FPRINTF_STRING );

    return 0;
}

Originally Posted by gfotedar

@Adak Thanks the double % worked!!

Gaurav.

You don't *HAVE* to act so surprised, you know!

No I've already tried it, its printing %e

Because you hard code it inside the fprintf statement, if you create a variable it wont.

Originally Posted by quzah

To write %%e you would have to use:

Code:

fprintf( fp, "%%%%e" );

Not if the string is a variable like the example I gave.

Code:

const char *printf_string = "fprintf(of \"AC\\nGain=%%e\\nPhase=%%e\\nUGF=%%e\\n\\n\", Gain, x, ugf)";
printf("%s\n", printf_string );