Thread: Stack Problem

Originally Posted by livin

In other words, what is the scope of a pointer which is dynamically initiated?

Thanks,
Livin

The pointer will also be destroyed, but the address it contains will be valid until that region is freed. When you return from such a function you could return the value (i.e the address on the heap) but not the pointer it self.

Code:

char *foo() {
     char *p = malloc( 16 * sizeof(char) );
     if(!p) return NULL;
     
     return p;
}