seq function in C

[reine]

Hello guys, I have been learning C for just under a week now and the first assignment is giving me quite a bit of trouble. We are supposed to write the seq function in linux (seq: sequence of numbers (linux)) in C. My current hurdle is how can I have multiple parameters in my input? that is, how can i have my program read whether there are 1, 2, or 3 integers in the input? the following two programs were given to us to help us btw

 #include   int main(int argc, char *argv[])  { 	 int i;  	 printf("argc = %d\n", argc);  	 for (i = 0; i < argc; i++) 		 printf("argv[%d] = %s\n", i, argv[i]); }

and

 #include    int main(int argc, char *argv[])  { 	 int i;  	 i = atoi(argv[1]); 	 	 printf("%d\n", i);  }

[Ocifer]

Since this is for school, and there's a policy against giving answers out, I'll give you a strong hint:

look up "argc" and "argv".

They play an important role that will be obvious if you google.

[parimal.s.dave]

Its easy go through the link :

Chapter 13: Reading the Command Line

[reine]

thanks for the help!

so i'm using code::blocks, how do i pass arguments to the programme? I see how it's done in command prompt

[stahta01]

thanks for the help!

so i'm using code::blocks, how do i pass arguments to the programme? I see how it's done in command prompt

Passing command line arguments in Windows 7

Tim S.