this code is not running
but this code is running.Code:#include<stdio.h> int pa(int [] ,int); main() { int a[4]={10,20,30,40}; pa(a,3); } int pa(int a[],int ub) { int k=0; printf("%d",a[k]); if(k!=ub) pa(a,k+1,ub); }
i think they should give the same output.Code:#include<stdio.h> int pa(int [],int ,int); main() { int a[4]={10,20,30,40}; pa(a,0,3); } int pa(int a[],int lb,int ub) { printf("\n%d",a[lb]); if(lb!=ub) pa(a,lb+1,ub); }
The first one wont even compile because you're trying to pass three parameters to pa but pa is declared as only taking two.
It can work just as well if given the correct parameters though.
Clearly the bottom one also includes a newline however, where the top one does not. So you have no reason to think that they would produce the exact same output.
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To make the first one work, I guess you could try
pa(a+1,ub-1);
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