Parse error on line 28 and 36

[jollykiddo]

Hi guys, I'm trying to learn how to read and print a matrix using C. I wrote the following code. However, the compiler gave me this error.

tutorial_10_qn3_tryagain.c: In function `readMatrix':
tutorial_10_qn3_tryagain.c:28: error: parse error before '(' token
tutorial_10_qn3_tryagain.c: In function `printMatrix':
tutorial_10_qn3_tryagain.c:36: error: parse error before '(' token

I'm not sure what's wrong. I counted the brackets and made sure I did not miss out any, neither did i miss out ';'. Can you please advise what's wrong. thanks.

  #include <stdio.h>
 
 struct Matrix
 {
    int rows; int columns;
     int mat [10][10];
 };
 
 void readMatrix (struct Matrix *M);
 void printMatrix (struct Matrix M);
 
 int main ( )
 {
      struct Matrix M ={0,0,{{0}}}, *ptr;
     ptr= &M;
     readMatrix(&M);
     printMatrix(M);
 
     return 0;
 }
 
 void readMatrix ( struct Matrix *M)
 {
     int i=0; int j=0;
     scanf("%d %d", &((*M).rows), &((*M).columns));
     for ( i=0; i<((*M).rows); i++)
         for (j=0; j<((*M).columns); j++)
             scanf("%d",& ((*M).(mat[i][j])));
 }
 void printMatrix (struct Matrix M)
 {
     int i=0; int j=0;
     for (i=0; i<(M.rows); i++)
        {
            for (j=0; j<(M.columns); j++)
             printf("%d", (M.(mat[i][j])));
           printf("\n");
          }
  }

[jollykiddo]

Oh...sorry guys...i got it....i realised when i removed all the brackets and merely type these...it works....hmmm....is the brackets obstructing something?

scanf("%d",&(*M).mat[i][j]);
printf("%d",M.mat[i][j] );

[jollykiddo]

Sorry guys, could u teach me the following?

1) How do i print the brackets properly for my matrix in c such that the output is like that?http://upload.wikimedia.org/wikipedi...fc41990150.png

Currently the code i edited (below) only allows the matrix to be printed like that.

[ 1 1 2
2 4 -3
]


Can you teach me how to print the brackets properly?

  1 #include <stdio.h>
  2 
  3 struct Matrix
  4 {
  5     int rows; int columns;
  6     int mat [10][10];
  7 };
  8 
  9 void readMatrix (struct Matrix *M);
 10 void printMatrix (struct Matrix M);
 11 
 12 int main ( )
 13 {
 14     struct Matrix M ={0,0,{{0}}}, *ptr;
 15     ptr= &M;
 16     readMatrix(&M);
 17     printMatrix(M);
 18 
 19     return 0;
 20 }
 21 
 22 void readMatrix ( struct Matrix *M)
 23 {
 24     int i=0; int j=0;
 25     scanf("%d %d", &((*M).rows), &((*M).columns));
 26     for ( i=0; i<((*M).rows); i++)
 27         for (j=0; j<((*M).columns); j++)
 28             scanf("%d",&(*M).mat[i][j]);
 29 }
 30 void printMatrix (struct Matrix M)
 31 {
 32     int i=0; int j=0;
 33     printf("[");
 34     for (i=0; i<(M.rows); i++)
 35        {
 36            for (j=0; j<(M.columns); j++)
 37             printf("%d  ",M.mat[i][j] );
 38           printf("\n");
 39         }
 40     printf("]");
 41 }

2) I'm puzzled to why adding some brackets creates errors. The code of the previous post was fine but i realised when i add brackets so that the code becomes like that (below), the compiler give me parse error. Can you please explain to me why is this so?

printf("%d", ((M).(mat[i][j])));

Please advise. Thanks

[Adak]

Oh...sorry guys...i got it....i realised when i removed all the brackets and merely type these...it works....hmmm....is the brackets obstructing something?

scanf("%d",&(*M).mat[i][j]);
printf("%d",M.mat[i][j] );


//            Try this:

scanf("%d",&M.mat[i][j]);
printf("%d",M.mat[i][j] );

In this part of the for loop, you have one too many '(' (left parenthesis):

j<((*M).columns);

You'll have far fewer errors if you use index/indices, instead of pointers, when working with arrays.

[jollykiddo]

okie. thanks