Thread: help me figure out a part of this short code...about pointers

Code:

#include<stdio.h>

int main(void)
{
 int x = 0;
 int z[] = {0,1,4,9,16,25,36,49,64,81};
 int *p = z

x= *(p+9) /*this will be 81*/ + *(p+3) /*this will be 9*/ + (10**(z+1)); /* i have no clue for this one*/
printf("x= %i\n", x);

return 0;

}

That was a tricky one, because to me, ** looked like it meant a power operator, as it does in Fortran and some other languages. I thought maybe there was a typing error in the code example above with a space missing so that it should have read

+ 10* *(z+1)

It turns out, space or not, it comes out to the same number without an overflow.

*(z+1) is the dereferenced 2nd element in z.

Correct, Sonny_E ** is does not exist as 'power' in C.