passing character arrays into function

[blindchicken11]

Hello. For this program I'm doing I'm trying to get a user to enter two words, have those words passed into a function which compares the two words and sets a char pointer to a certain sentence based on the comparison.

The error I'm getting is "too few arguments to function compare". Any idea what I'm doing wrong?

#include <stdio.h>
#include <string.h>


void compare(char string1[30], char string2[30]);
void main()
{
        char string1[30];
        char string2[30];


        printf("Please enter a word.\n");
        scanf("%s", string1);
        printf("Please enter a second word.\n");
        scanf("%s", string2);


        compare();


}


void compare(char string1[30], char string2[30])
{
char *msg = NULL;


        if(strcmp(string1, string2)>0)
        { msg = "First word is greater than the second."; }
        else if(strcmp(string1, string2)<0)
        { msg = "Second word is greater than the first."; }
        else
        { msg = "First word is equal to the second word."; }




printf("%s\n", msg);
}

Thanks!

[TheBigH]

Your function prototype says that "compare" takes two character arrays as its arguments. But then when you call it, you don't give it any arguments at all.

I think you want to do

compare( string1, string2 );

[Adak]

The call to compare requires (string1, string2) (the names of the arrays).

You're too quick, BigH!

[blindchicken11]

Yep that fixed it! Thanks you two!