What is this mean!
I saw following statement in a C program. But I do not understand what exactly it means.
It looks like a function but i see '=' and the pointer notation '*'; bit confused. Could anyone explain me what is that?Code:void (* const text[]) (void) = { &_one,two,three};
This program is for an microcontroller (Anyway it does not matter I guess)
Thanks in advance
It defines text as a array of const pointers to functions that accept no arguments and return void.
The stuff after the equals sign initialises the array. _one, two, and three are presumably all functions that accept no arguments and return void. So text is an array of three function pointers.
The const just means that the elements of the array cannot be changed after initialisation.
Hi Grumpy,
Thanks for great explanation! I understood alomost everything except the syntax.
I did little more research. Please look at this
This is a array for 4 function pointers.Code:int (*FunA[3])(float, char, char) = {one,two,three,four};
1. All these 4 function accept 3 values and their types are (float , char , char). Is it true?
2. All these 4 functins will return int. That means "FunA" can not have pointer of a function that returns float. Is it true?
3. If above two statements are true, What I understand is "arrary of function pointer is make sense when all functions are return same type and accepts same type". Is my understanding correct?
One more unrelated question
Waht is the difference of following two declaration
int *i;
int* i;
Again Thanks for your time!
