loop help print this

[gnomelook]

#include<stdio.h>

main()

{
 int n, c, k, space;
 
 printf("Enter the number of rows: ");
 scanf("%d", &n);
 
 space=n;
  
 for(k=n;k>=1;k--)
         {for(c=1; c<=space; c++)
                 printf(" "); space++;
                     for(c=1; c<=k; c++)
                          printf("%d",k);
                         printf("\n");
         }
 return 0;
 }

sss4
ss34
s234
1234

s for space....
can any one help me??

[gnomelook]

preview must be like this:
sss4
ss34
s234
1234

s= space

[Adak]

Well, right away, the number of spaces equals the current row number being printed - 1, if you assign the current row number to the total row number, and then decrement it, in the loop.

In this code you have a for loop that looks like it's nested inside another for loop, immediately above it, but it's not. Indent your code, and you'll be surprised how easy it is to find some errors, and for others to study it:

        for(c=1; c<=space; c++)
                 printf(" "); space++;
                     for(c=1; c<=k; c++)
                          printf("%d",k);


//it should look like (but I wouldn't use this logic).
        for(c=1; c<=space; c++)
           printf(" "); space++;
        for(c=1; c<=k; c++)
           printf("%d",k);

The second example of the code looks substantially different.

If the total row number to print is 4, you will start printing digits with that value as the current row number (4). If current row number is 3, you will print the current row number -1, or two digits. The starting digit will be the current row number (3).

Your for loop will thus start with the current row number (which starts with the total row number to be printed), and end with the total row number (4 in this case).

Give that a shot.

[gnomelook]

thanks sir..

[gnomelook]

can you post the right code?? please...