Thread: Implicit conversion between pointers?

I am reading K&R book. In section 5.3 there is this code:

Code:

    int a[10];
    int *pa;
    pa=a;

I think that should be:

Code:

    int a[10];
    int *pa;
    pa=(int *)a;

Because pa is a pointer to an integer and a is a pointer to an array of integers. Of course the first code works maybe because it happens an implicit cast (conversion). Am I right?

thanks